Resistance of the circuit

For 4 parallel resistors have equivalent resistance of:

$\begin{aligned} \dfrac{1}{R_{p}} &= \dfrac{1}{16} \Omega + \dfrac{1}{16} \Omega + \dfrac{1}{16}\Omega + \dfrac{1}{16}\Omega \\ &= \dfrac{4}{16}\Omega \\ \\ \implies R_{p} &= 4\Omega \end{aligned}$

There are 4 such combinations in series. Thus total resistance would be:

\[\begin{align} R &= 4 \times R_{p} \\ R &= 4 \times 4 \Omega \\ R &= \boxed{16 \Omega}

\end{align}\]