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Electricity and Magnetism Level pending

30 A 30\text { A} of current is being passed in a cylindrical wire of radius 5 1 0 7 m \dfrac{5}{10^7} \text{ m} and length 10 m 10\text{ m} .

If the angle between direction of magnetic field and current-carrying wire is 30 ° \ang{30} , find the magnitude of motion of conductor (or magnitude of force experienced).

Give your answer multiplied with 2 × 1 0 7 2 \times 10^7 or 20000000 20000000 , If your answer is 0.0000001 0.0000001 then your answer will be 1.


The answer is 1800.

Viki Zeta by Viki Zeta , 19, India

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1 solution

Viki Zeta
Aug 18, 2016

We know, magnetic field B = μ 0 I 2 π r ; μ 0 = 4 π × 1 0 − 7 B = 4 π × 1 0 − 7 ∗ 30 2 × π × 5 × 1 0 − 7 B = 12 T Next, we know that Force F = I B l s i n ( θ ) F = 30 × 12 × 5 1 0 7 × 1 2 F = 0.00009 Therefore your answer will be 0.00009 × 1 0 7 = 1800 \text{We know, magnetic field} \\ B = \dfrac{\mu_0 I}{2\pi r}; \mu_0 = 4\pi \times 10^{-7} \\ B = \dfrac{4 \pi \times 10^{-7} * 30}{2 \times \pi \times 5 \times 10^{-7}} \\ B = 12 T \\ \text{Next, we know that Force} \\ F = IBlsin(\theta) \\ F = 30 \times 12 \times \dfrac{5}{10^7} \times \dfrac{1}{2} \\ F = 0.00009 \\ \text{Therefore your answer will be} \\ 0.00009 \times 10^7 = \fbox{1800}

2 Helpful 0 Interesting 0 Brilliant 0 Confused

The I in F=ILxB is supposed to be the current in the conductor under motion.

Pratyush Pandey - 4 years, 7 months ago

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30 A 30\text { A} of current is being passed in a cylindrical wire of radius

Viki Zeta - 4 years, 7 months ago

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