Resistors in infinite series

$\text{For} \space a > 1: \\ R = \tau (a) = \sum_{n=0}^{\infty} \frac{1}{a^n} = \frac{a}{a-1} \\ and \\ V = IR$

A circuit consisting of an infinite series of resistors is prepared such that the simplified equivalent resistor has a resistance ( $R$ ) equal to $\tau (a)$ . Determine the voltage ( $\text{V}$ ) a circuit that has a resistance of $\tau (5) \space Ω$ and a current ( $\text{I}$ ) of $16 \space A$ .

Give your answer in volts.