Resolving Constrains!!

Classical Mechanics Level 4

As The Figure Shows,Then Let v 0 v_0 be the Velocity Of the Block A.

Find 10 3 v 0 {10}^{3} v_0 .

Details And Assumptions \textbf{Details And Assumptions}

v of Block B = 12.35 m / s e c v \text{ of Block B} = 12.35 m/sec , x = 7 m x = 7 m And Height h = 24 m h = 24 m


The answer is 1729.

Vraj Mehta by Vraj Mehta , 30, India

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1 solution

Again 1729 1729 !

By virtual work method, we get :

T c o s ( θ ) v B = 2 T v 0 Tcos(\theta)v_B=2Tv_0

Where T T is tension in the rope. c o s ( θ ) = x / ( x 2 + h 2 ) 0.5 cos(\theta)=x/(x^2+h^2)^{0.5}

On solving, we get desired answer.

Classic JEE style.

7 Helpful 0 Interesting 0 Brilliant 0 Confused

The beaty of Ramanujan no. In physics 12^3+1^3=10^3+9^3=1729

devansh shringi - 6 years, 3 months ago

Nice And Short.+1

P.S I am way too fond Of 1729 1729

Vraj Mehta - 6 years, 3 months ago

I don't get this method u used, what I try to use was the energy conservation theorem, mgh + 0.5mv^2,=mgh + 0.5mv^2, please explain to me how u did it, you can sent it to my email ogedengbeabdullah@gmail.com thank you

ogedengbe abdullah - 6 years, 3 months ago

Log in to reply

A bit lengthy E mail address!

Muhammad Arifur Rahman - 6 years, 3 months ago

Look up virtual work method on the internet. It is an easy way to do constraint problems.

Raghav Vaidyanathan - 6 years, 3 months ago

Did the same thing.

Purushottam Abhisheikh - 6 years, 3 months ago

Nice one.. The moment I saw the number 1729, I knew it was correct... :D

Sparsh Sarode - 4 years, 2 months ago

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