Resolving some force #1

Classical Mechanics Level 2

A force of $\text{1000 N}$ is to be resolved into 2 components along line $AA$ and $BB$ . If component along line $BB$ is $\text{350 N}$ , find angle $\alpha$ and component along $AA$ ?

Note : $F_{a-a}$ and $F_{b-b}$ are components along line $AA$ and $BB$ respectively.

\alpha = 14.33^{\circ}

and

F_{a-a} = 1216.39 N

\alpha = 15.38^{\circ}

and

F_{a-a} = 1213.37 N

\alpha = 17.05^{\circ}

and

F_{a-a} = 1316.36 N

1 solution

Rajesh Khanna
Aug 29, 2015

On using sin rule in the small triangle to the right . 350/sin(alpha)=1000/sin(45)=F{a-a}/sin(135-alpha). and from here equating the first two and last 2 .you will get the answer.

Resolving some force #1

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