Restrictions Matter!

Algebra Level 3

{ x = e t y = e 2 t 1 \begin{cases} x = e^t \\ y = e^{2t} - 1 \end{cases}

What is the shape of the curve described by the above parametric equation?

Line Circle Semicircle Parabola Half of a parabola

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2 solutions

Chung Kevin
Oct 13, 2015

At first glance, this looks like a parabola because we can rewrite y = e 2 t 1 y = e^{2t} - 1 as y = ( e t ) 2 1 y = (e^t)^2 - 1 , which can be rewritten through substitution as y = x 2 1 y = x^2 - 1 .

However, x = e t x = e^t doesn't take on zero or any negative values, so the left hand side of the standard parabola y = x 2 1 y = x^2 - 1 is not drawn. Therefore, the answer is half of a parabola.

Exactly same way

Paola Ramírez - 5 years, 8 months ago

very clever

rajdeep das - 4 years, 11 months ago
Rohan Joshi
Jan 10, 2021

It’s pretty ez to see by substitution that it’s a parabola. But notice that x=e^t is always gonna be positive, so for any value of t, x is positive, so only half a parabola is traced out.

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