P Q R S is a rhombus. P R and Q S are its two diagonals, with respective lengths 6 cm and 4 cm.
What is the area of the rhombus?
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Given the lengths of the diagonals of a rhombus, the area is 2 1 multiplied by the product of the diagonals. So the area is 2 1 × 6 × 4 = 1 2 cm .
The area of rhombus is
2 s i d e x ∗ s i d e y = 2 ( 6 ) ( 4 ) = 1 2
The area of a rhombus given the two diagonals is
A = 2 1 ( d 1 ) ( d 2 ) = 2 1 ( 6 ) ( 4 ) = 1 2 c m 2 answer
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The length of two diagonals of rhombus, PR = 6 cm and QS = 4 cm
The area of the rhombus,
= 2 1 × PR × QS square single
= 2 1 × 6 × 4 Square cm
= 12 Square cm (Answer)