Rhombus

Geometry Level 2

P Q R S PQRS is a rhombus. P R PR and Q S QS are its two diagonals, with respective lengths 6 6 cm and 4 4 cm.

What is the area of the rhombus?

12 square cm 10 square cm 19 square cm 8 square cm 20 square cm 7 square cm

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4 solutions

Munem Shahriar
Apr 26, 2017

The length of two diagonals of rhombus, PR = 6 cm and QS = 4 cm

The area of the rhombus,

= 1 2 \frac{1}{2} × PR × QS square single

= 1 2 \frac{1}{2} × 6 × 4 Square cm

= 12 Square cm (Answer)

Given the lengths of the diagonals of a rhombus, the area is 1 2 \dfrac{1}{2} multiplied by the product of the diagonals. So the area is 1 2 × 6 × 4 = 12 cm \dfrac{1}{2} \times 6 \times 4 = \boxed{12~\text{cm}} .

The area of rhombus is

s i d e x s i d e y 2 \frac{side\ x\ *\ side\ y}{2} = = ( 6 ) ( 4 ) 2 \frac{(6)(4)}{2} = = 12 12

The area of a rhombus given the two diagonals is

A = 1 2 ( d 1 ) ( d 2 ) = 1 2 ( 6 ) ( 4 ) = A=\dfrac{1}{2}(d_1)(d_2)=\dfrac{1}{2}(6)(4)= 12 c m 2 \boxed{12~cm^2} answer \boxed{\text{answer}}

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