There is a rhombus of which three vertices lies on a circle on a circle, and fourth vertex at center. If area of the rhombus is 32 3 sq. cm, then find the radius of the circle in cm.
This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try
refreshing the page, (b) enabling javascript if it is disabled on your browser and,
finally, (c)
loading the
non-javascript version of this page
. We're sorry about the hassle.
by analysis the side of the rhombus is equal to the radius and the area of the rhombus is equal to the area of an equilateral triangle x 2
Diagonal of a rhombus are at right angles. One diagonal is R cm long. The sides are also R cm long.
Two semi-diagonals form a right angled triangle with one side. The sides of this triangle are is R/2 for one semi-diagonal, and R for the side of the diagonal that is the hypotenuse.
So this is a 30-60-90 triangle, area =
2
R
2
∗
3
for 1/4 of the rhombus.
Full area = 4 ∗ 2 R 2 ∗ 3 = 2 ∗ R 2 ∗ 3 = 3 2 ∗ 3
R = 8
How to insert a diagram in this?? For posting a problem or a note we can take a PNG file and post it on it. But how to do it here or in comment?
Problem Loading...
Note Loading...
Set Loading...
area of that rhombus will be r*r root3/2