Riddle! Riddle!

All numbers are either in ones, tens, hundreds, thousands, etc.

The number is a two digit number. This means that it is written in tens

For example: 21 can be written as 20+1, also as 10(2)+1, 32can also be written as 30+2, also 10(3)+2

Let our two digit number be $xy$

We can therefore write it as $10(x)+y$

Remember that the sum of the digits is 11, meaning $x+y=11$

And when it is written in the reverse order, it is 9 more than the original number. Meaning, $yx=xy + 9$ . In other words, $10y+x=10x+y+9$

That becomes $9y=9x+9$ Then, $y=x+1$ , after dividing through by 9.

Placing the $y=x+1$ into our previous equation, $x+y=11$

We have $x+x+1=11$

$2x+1=11$

$2x=10$

$x=5$

From the equation, $x+y=11$ , if $x=5$ , then $5+y=11$

$y=6$

Since our two digit number is represented by $xy$ our answer is $56$

so, 1. try listing all numbers that make 11 1+10 2+9 3+8 4+7 5+6 2. 1+10 does not work because it is double digits 3. write both of the numbers 29, 92 38,83 47,74 56,65 4. check which one is 9 more when written in reverse (above)

THE ANSWER IS 56!!!! PLEASE LIKE OR SHARE

if you know that both digits are separated by 9, it means they are close numbers, and if they both sum 11, it means that from the possible sums to 11, it's also the closest numbers, so from the sums to 11, they can be: 11+0, 10+1, 9+2, 8+3, 7+4 or 6+5, being 6+5 the closest numbers between them. this means the number is formed by 6 & 5, as the problem says to look for a number that adding 9 is the same digits in the reverse order, you are looking for the smallest term with this digits, bieng 56 smaller than 65, this is the answer (56)

Lol, I just thought of the first way that came in to my head to get to 11, 5+6, and realised if you reversed it, it was 9 more. Because 5 and 6 are consecutive numbers. Like 34 and 43.

since sum of the two digit number is 11, the two digit numbers that give the sum 11 is 29, 38, 47, 56,65, 74, 83, 92. the reverse order that gives 9 more than that two digit number is 56.

Since the information provided is thatThe sum of my digits is 11. When written in the reverse order, I am 9 more than the original number. Therefore the order will start from 29 38 47 56 65 74 83 And 92 Now we will see the numbers having the same digits and then subtract the greatest number from the original number. (65-56=9) Hence calculated.

Basically, what 2 digit number adds up to 11, but is 9 apart from its reverse?

First thing I did is look at multiples of 9, because that is how far it is from its reverse: (18, 27,36,45,54,63,72,81,90,99) The only issue is if you want them to add up to 11, not to to 9, which they all (except 99) do.

The easy solution is to that is to add 2 to all of them: (20,29,38,47,56,65,74,83,92,101) You can easily get rid of the ones that do not add up to 11 (29,38,47,56,65,74,83,92)

Since they are all 9 apart from each other, you want 2 numbers that appear side by side in the list, that are reverse of each other. The only pair that matches this description is: (56,65)

You know the original is 9 less than the reverse, so the answer must be 56.

There is probably better ways to answer this, but this is the way I came at it. I chose the 9 apart because of the nature of multiple of 9's being reverse each other and always adding up to the same thing (9).

If $a$ is the tens and $b$ is the ones, then the number is $10a+b$ . If it is written in reverse order, it will become $10b+a$ .

$10b+a$ is $9$ more than $10a+b$ , therefore $10b+a=10a+b+9$ , hence: $b - a = 1$

Since $a+b=11$ , we can eliminate one variable to get another. $a=5$ , $b=6$ .

The number is $10a+b = 10(5) + 6 = 56$ .

we have that system of two equations: 1: x+y = 11 2: 10x + y = (10y +x) + 9 1: x+y = 11 2: 9(x-y)= 9 1: x+y = 11 2: x-y = 1 1+2 : 2x = 12 .. x = 6 1 -2 : 2y = 10 .. y = 5 hence the number is 56

What i did is to understand the riddle itself.
There are possible answers but when it was said "When i am written in reverse order, I am 9 more than the original number"

all i can think was 5 and 6 so 56

the reverse part was when it is 6 and 5 so 65

what is did is 65-56 = 9

also, commonplace, just by thinking the reverse of 9 is 6. i think that makes sense. Hahahahaha

so yeah, 56.

Let 10's digit=x &one's digit = y Then original number be 10x+y. If the digit reverse, New number 10y+x: 10y + x - (10x + y} = 9 ie 9y - 9x = 9 => -x + y = 1...(1)and x + y = 11...(2) Adding these equation 2y=12 =>y=6; y on equation(2) x=5 So the Number is 56.