A rocket is flying along the diagonal of a square field of area 0.5sq km with a velocity 2.8E8 ms^-1.find the magnitude of the area of the field to the rider of the rocket.(in sq km)
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side of the square=.707km. so,diagonal of the square=1km The diagonal the rocket is flying along will shorten to, d2=1 (1-(v^2/c^2))^1/2 =.3509km. no change will occur in the other diagonal,since it is perpendicular ti the direction of motion. so,d1=1km. so, new area=.5 d1*d2=.179km