Riemann- zeta function (III)

Calculus Level 5

True or false? 1 2 ( π z cot ( π z ) 1 ) = n = 1 ζ ( 2 n ) z 2 n \displaystyle \frac{-1}{2} \left (\pi z \cot (\pi z) - 1 \right) = \sum_{n = 1}^{\infty} \zeta (2n) z^{2n} in D ( 0 , 1 ) C D(0, 1) \subset \mathbb{C} , after eliminating the avoidable singularity of π z cot ( π z ) \pi z \cot (\pi z) at z = 0 z = 0 .

Note.-

a) ζ ( ) \zeta ( \cdot ) is Riemann zeta function .

b) we are assuming Axiom of Choice according to main principles of "constructive mathematics".

True Both, (true and false) False Undecidable in Zermelo Fraenkel Choice

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