Riemann's Zeta function

We know that $\zeta(s)=\displaystyle \sum_{i=1}^{\infty} \frac{1}{i^s}$ .

So $\frac{1}{2^s}+\frac{1}{4^s}+\frac{1}{6^s}+...=\frac{1}{2^s} \displaystyle \sum_{i=1}^{\infty} \frac{1}{i^s}=\frac{1}{2^s}\zeta(s)$ .

So $α=\frac{1}{2}=\boxed {0.5}$ .

Common out 1/2^s from series,we will directly get our solution....and i suggest it should be in algebra not calculus