Right integral triangles

Number Theory Level pending

Answer true or false on the following statement:

An integral right angle triangle can have its area as a perfect square number.

True False

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1 solution

The sides of an integral right triangle are of the form a 2 b 2 , 2 a b , a 2 + b 2 a^2-b^2, 2ab, a^2+b^2 , where a , b a, b are positive integers. Area of such a triangle is a b ( a 2 b 2 ) = b 4 x ( x 2 1 ) ab(a^2-b^2)=b^4x(x^2-1) , where x = a b x=\dfrac {a}{b} . Now either one or none of x x and x 2 1 x^2-1 can be a square. Hence the area can never be a perfect square .

This is not correct. Which integers n , a n,a correspond to a 5 , 12 , 13 5,12,13 right triangle?

(Also: Why can't the product of three consecutive (positive) integers be a perfect square?)

Patrick Corn - 1 year, 2 months ago

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For all positive integers n n , there is no common factor of n n and n 2 1 n^2-1 . Even if n n be a perfect square, n 2 1 n^2-1 is never a perfect square. So n ( n 2 1 ) n(n^2-1) is never a perfect square. Regarding your first question, I have changed the expressions for the side lengths of the triangle.

A Former Brilliant Member - 1 year, 2 months ago

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Agreed on your argument for the second question.

Patrick Corn - 1 year, 2 months ago

After the edit, this argument continues to need more detail. If x x is rational, why can't x x and x 2 1 x^2-1 be perfect squares? Note that x 2 1 x^2-1 can be a perfect square, e.g. x = 5 / 4. x = 5/4. You need more explanation.

Patrick Corn - 1 year, 2 months ago

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