RLC at DC
A DC voltage source supplies a network of resistors, capacitors, and inductors, as shown above. All resistances are , all inductances are , and all capacitances are . The DC source voltage is .
If the circuit is in DC steady-state, how much current (in amps) flows through the source?
The answer is 6.667.
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1 solution
All you have to remember is that in steady state, RC blocks act as open circuits and RL blocks act as short circuits.
Therefore, no current will flow through C (infinite resistance) and L will have zero resistance (a straight normal wire). So in the parallel RL circuit, the current will not flow through R at all as current has the tendency to follow the path inversely proportional to impedance.
V = DC Voltage, i = DC Current
Hence, V = i x [ R + R R . R + R]
Or, 10 = 2 3 . i ; Given R = 1 Ohm
Or, i = 6.67 A