RLC circuit 2

In the above diagram, a resistor with resistance R R , a capacitor with capacitance C , C, and two inductors with self-inductances L L and 2 L , 2L, respectively, are connected to an AC power supply. The frequency of the AC power supply is 1 2 π L C \displaystyle \frac{1}{2\pi \sqrt{LC}} . Which of the following statements is correct?

a) When the switch S is connected to A , the impedance of the circuit is R R .
b) When the switch S is connected to A , the voltages across the resistor and the capacitor have the same phase angle.
c) The RMS value of the current is smaller when the switch S is connected to B than when it is connected to A .

b) only a) only a) and c) b) and c)

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2 solutions

Shaik Jaffer
Apr 16, 2014

At resonance the impedance of the inductance is equal to the impedance of the capacitance. ie X L=X C ; X=2 x pi x frequency.When you do plug in the values of the variables you find out it is true.Hence since L and C are opposites of each other they cancel and the only impedance is R. Since the impedance has dropped to R the value of current increases hence its RMS value also increases. (i have explained it very poorly but do try to get the idea.)

Alinjar Dan
Apr 23, 2014

Shaik is exactly true.

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