RMO 4

Find the number of positive integers < 3600 which are coprime to 3600.


The answer is 960.

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2 solutions

Kalpok Guha
Dec 23, 2014

ϕ ( 3600 ) \phi(3600) = ϕ ( 5 2 ) \phi(5^2) ϕ ( 3 2 ) \phi(3^2) ϕ ( 2 4 ) \phi(2^4)

ϕ ( 5 2 ) = 5 2 5 1 \phi(5^2)=5^2-5^1

ϕ ( 3 2 ) = 3 2 3 1 \phi(3^2)=3^2-3^1

ϕ ( 2 4 ) = 2 4 2 3 \phi(2^4)=2^4-2^3

Thus ϕ ( 3600 ) = 20 6 8 = 960 \phi(3600)=20*6*8=960

The answer is 960 960

Are you Serious, Is this really a RMO problem?

Swapnil Das - 5 years, 10 months ago

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I was also thinking this :P

Md Zuhair - 3 years, 8 months ago

I don't think it is a RMO problem.

Kalpok Guha - 3 years, 8 months ago

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Without using Euler's Totient func. it will be RMO lvl question then

Md Zuhair - 3 years, 8 months ago

use euler's phi function.

what i have done wrong if i count the factors of 3600 then subtract it from 3600

Dheeraj Agarwal - 6 years, 8 months ago

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54 is not a factor of 3600 but gcd(54, 3600) != 1.

Vishal Antony - 6 years, 5 months ago

can u give a little more explanation

Ashwani Singh Tanwar - 6 years, 6 months ago

Yes exactly....

Jayakumar Krishnan - 6 years, 9 months ago

Hi.Rajarshi! Why didn't you show up in tution? (Dont think this a comment)

Chandrachur Banerjee - 6 years, 9 months ago

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which tution

Kaustubh Miglani - 5 years, 11 months ago

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the one i which u forgot your name ,ha ha

Chandrachur Banerjee - 5 years, 11 months ago

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