Let be a polynomial of degree 2015 which satisfies for all . If the value of can be expressed as
where and are coprime integers and is a prime, find the value of .
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P (x) can be written as xC1 +xC2+xC3+........xC2015 +1 Now substituting x=2016 We get 2^2016-(2016C0) =2^2016 -1 We get 2+2016+1=2019