Let ABCD be a unit square. Draw a quadrant of circle with A as centre and B,D as end points of the arc. Similarly , draw a quadrant of a circle with B as centre A and C as end points of the arc. Inscribe a circle S touching arcs AC and BD both externally and also touching the side CD. Find the radius of the circle S
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we can easily prove that AOE congruent to BOE(R.H.S.)
therefore, AE=EB=1/2
By pythagoras theorem A O 2 = A E 2 + E O 2
or, ( R + r ) 2 = ( R − r ) 2 +1/4
or, ( 1 + r ) 2 = ( 1 − r ) 2 +1/4 [as R=1]
or, r = 1/16
or, r=0.0625