Road race

Two cars are at a red light, just at the beginning of a 90 ^{\circ} left turn on the road. The cars are next to each other 5 m 5\text{ m} apart, and they start exactly at the same time when the light turns green. The car on the inside of the turn makes a quarter circle of radius 10 m , 10\text{ m}, while the car on the outside makes the turn on a circle of radius 15 m. 15\text{ m.} The centers of the turning circles coincide.

As they accelerate in their turns, they keep going head-to-head, i.e. the line connecting the drivers' heads keeps pointing to the common center of the turning circles. Then they reach the straight section of the road at the same time, with each car stopping accelerating and moving with constant velocity afterwards.

Where is the outside car at the moment when the inside car is 25 m 25\text{ m} out of the turn?

Note: The illustration is not drawn to scale.

12.5 m 12.5\text{ m} ahead of the inside car 12.5 m 12.5\text{ m} behind the inside car 25 m 25\text{ m} ahead of the inside car 25 m 25\text{ m} behind the inside car They will be head-to-head Information missing, impossible to answer

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

Laszlo Mihaly
Apr 19, 2018

In a time interval of Δ t \Delta t the cars move a distance of Δ α R 1 \Delta \alpha R_1 and Δ α R 2 \Delta \alpha R_2 , where R R is the radius of the turning circle and Δ α \Delta \alpha is the change in the angle of the line connecting the driver's head, measured at the center of the turning circle. Using v 1 = R 1 Δ α / Δ t v_1=R_1 \Delta \alpha/\Delta t and v 2 = R 2 Δ α / Δ t v_2=R_2 \Delta \alpha/\Delta t and dividing the two equations we get v 2 / v 1 = R 2 / R 1 v_2/v_1=R_2/R_1 This relationship holds at any moment while they are in the turn. In particular, it holds at the moment when they exit the turn, and determines the ratio of the velocities after the turn. After exiting the turn the distance traveled by each car is s 1 = v 1 t s_1=v_1 t and s 2 = v 2 t s_2=v_2 t , therefore s 2 / s 1 = v 2 / v 1 s_2/s_1=v_2/v_1 . The distance between the cars is s 2 s 1 = ( v 2 / v 1 1 ) s 1 = ( R 2 / R 1 1 ) s 1 = 12.5 m s_2-s_1=(v_2/v_1-1)s_1=(R_2/R_1-1)s_1=12.5m

It is interesting that the problem can be solved without knowing the actual velocities or accelerations. In fact, the cars do not have to accelerate uniformly; the only requirement is that they travel head to head during the turn.

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...