Roll the dice

Probability Level pending

Peter rolls a pair of dice with the integers 1 through 6 on the faces of each die. What is the probability that the sum of the integers on the top faces is 9?

1/9 2/3 9999999/10000000 4/9 2/9

Remy Xiao by remy xiao , 14, China

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3 solutions

Marvin Kalngan
May 6, 2020

Total Number of Possible Outcomes=4 : [ 3 + 6 , 6 + 3 , 4 + 5 , 5 + 4 ] {\text{Total Number of Possible Outcomes=4}}:[3+6, 6+3, 4+5, 5+4]

Number of Favorable Outcomes = 6 2 = 36 \text{Number of Favorable Outcomes}=6^2=36

Probability of an Event = Number of Favorable Outcomes Total Number of Possible Outcomes = 4 36 = 1 9 \text{Probability of an Event}=\dfrac{\text{Number of Favorable Outcomes}}{\text{Total Number of Possible Outcomes}}=\dfrac{4}{36}=\boxed{\dfrac{1}{9}}

1 Helpful 0 Interesting 0 Brilliant 0 Confused

Since the sum is 9 9 and a dice is random, the answer is 1 9 \frac{1}{9}

1 Helpful 0 Interesting 0 Brilliant 0 Confused

Well that's just a coincidence

remy xiao - 1 year, 1 month ago

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If you mean ' a dice is random', than yes.

A Former Brilliant Member - 1 year, 1 month ago

I mean 4+5 and 3+6 all result in nine .,so 1/9 is quite coincident

remy xiao - 1 year, 1 month ago

I mean 4+5 and 3+6 all result in nine .so 1/9 is quite coincident

remy xiao - 1 year, 1 month ago
Mahdi Raza
May 7, 2020

\[\begin{array}{c|cccccc} &1 &2 &3 &4 &5 &6 \\ \hline \\ 1& 2& 3& 4& 5& 6& 7& \\ 2& 3& 4& 5& 6& 7& 8& \\ 3& 4& 5& 6& 7& 8& {\color{Blue}{9}}& \\ 4& 5& 6& 7& 8& {\color{Blue}{9}}& 10& \\ 5& 6& 7& 8& {\color{Blue}{9}}& 10& 11& \\ 6& 7& 8& {\color{Blue}{9}}& 10& 11& 12& \end{array}

\implies \frac{4}{36}

\implies \boxed{\frac{1}{9}}\]

0 Helpful 0 Interesting 0 Brilliant 0 Confused

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