Roll the dice thrice 1

A fair dice is numbered with 1 , 2 , 0 , 1 , 3 , 2 1,-2,0,-1,3,2 on its faces.

The probability of getting a sum of 6 after rolling the dice thrice can be expressed as a b \frac{a}{b} where a , b a,b are relatively prime.

Find a + b a+b .

Try these too: Part II , Part III
Image Credit: Flickr Gard Rimestad .


The answer is 113.

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1 solution

Aditya Virani Staff
Jun 11, 2015

Possible results of the three trials (unordered) are ( 1 , 2 , 3 ) , ( 2 , 2 , 2 ) , ( 0 , 3 , 3 ) . (1,2,3),(2,2,2),(0,3,3). There are 6 ways to order ( 1 , 2 , 3 ) , (1,2,3), 1 way to order ( 2 , 2 , 2 ) , (2,2,2), and 3 ways to order ( 0 , 3 , 3 ) , (0,3,3), which gives the probability 6 + 1 + 3 6 3 = 5 108 . \frac{6+1+3}{6^3}=\frac{5}{108}.

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