Rolling a Perfect Square

• Find the number of integers between 1 and 20 that are perfect squares.

1, 4, 9, 16

There are 4 perfect squares.

• Next, find the probability (a/b) of a perfect square being rolled on the 20-sided die.

(number of sides with perfect squares)/(total number of sides) = 4/20

• Let's check to ensure that the numerator and denominator are coprime integers. (Coprime integers are integers with no common factors.)

4 and 20 have - oh, no! - 2 common factors other than 1!

Let's try simplifying 4/20 to see if that helps.

4/20 = 1/5

1 and 5 are coprime integers! Yay!

• Finally, let's sum up our a and our b, which are, respectively, 1 and 5

1 + 5 = 6

The probability that the answer will be any number [from 1 to 20] of a 20-sided fair die is $\frac{1}{20}$

And there is 4 perfect squares from 1-20 which are 1, 4, 9, 16

So the probability that the answer will be a perfect square of 20 numbers is $\frac{4}{20} \implies \frac{1}{5}$

And, the answer is $1+5 \implies \boxed{6}$

as perfect squares=(1,4,9,16)

P(1,4,9,16)=4/20=1/5=a/b....

Therefore,a+b=1+5=6....

the possible outcomes are 1,4,9,16 therefore there are 4 possible ways of getting a perfect square

hence P(E)=4/20 =1/5=6

Since this question is based on probability the a= what you want (In this case perfect squares), while the b= what you could get (TOTAL possibilities). The total number of possibilities is the numbers from 1-20 which is 20, making b=20. To find "a" list all the perfect squares from 1-20; 1,4,9,16. Since their are four perfect squares a= 4. Making the fraction 4/20 which in simplest form is 1/5. And 1+5= 6, making the answer 6.

probability is 4/20 (4 because we have 16,9,4,1) so 4/20 = 1/5 => 5+1 = 6

1,4,9 and 16 are perfect squares from 1 to 20.
Then probability of their occurrence is 4/20=1/5 So 1+5=6

the squares would be 1, 4, 9, 16. thus the probability is 4/20, i.e 1/5. Hence, 1+5 =6

total:= 20 numbers; Possibilities of perfect squares:= 4;

Dividing each other:= /frac{4}{20} = /frac{1}{5}

Soon: a+b = 1 + 5 = /boxed{6}

P[E]=Number of favourable outcomes/Total number of out comes. Total number of outcomes is 20. Number of favourable outcomes=1,4,9,16=4 terms. Probability =4/20=1/5 which are co-primes. a+b=6.

• No intervalo de 1 a 20 os quadrados perfeitos são os seguintes: 1,4,9,16.

A probabilidade será: $\frac{4}{20}$ = $\frac{1}{5}$ ------> 1+5 = $\boxed{6}$

Total possibilities = 1, 2, 3, ... 19, 20. (total = 20)

Perfect square possibilities = 1, 4, 9, 16. (total = 4).

Probability = 4/20 = 1/5, i.e. a = 1 & b = 5.

the perfect squares from 1 to 20 are 1,4,9, and 16

probability=4/20=1/5

so a+b = 1+5=6

The set $\{1,2,3,...,20\}$ has four perfect squares which are $1,4,9,16.$ Thus the probability is $\frac{4}{20}=\frac{1}{5},$ so $a+b=\boxed{1+5=6}$ .

1, 4, 9 and 16 are the only perfect squared under 20. So it is a 4 in 20 chance, or 1 in 5 when reduced. 1+5 sum up to 6.

There are 4 perfect squares less than 20, namely

1^2 = 1, 2^2 = 4, 3^2 = 9, and finally, 4^2 = 16

Therefore, 4 out of 20 possibilities are perfect squares.

As such, there is a 4/20 or a 1/5 chance that you roll a perfect square

1 + 5 = 6, hence the answer

Let the Set A = {1, 2, 3, 4... 20} and B = {1, 4, 9, 16}. It's easy to see that B ∈ A. The probability P of choice an element which belongs to B and to A simultaneously is, n(A∩B)/n(A).

So, P = 4/20 = 1/5.

1+5 = 6.