rolling ball
A spherical ball of mass 20 kg is stationary at the top of a hill of height 100 m. It rolls down a smooth surface to the ground, then climbs up another hill of height 30 m and finally rolls down to a horizontal base at a height of 20 m above the ground. The velocity attained by the ball is?
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1 solution
The ans would come if we don't consider rolling motion which I think is wrong. The ans for the ques is :
Net gain in kinetic energy = Net loss in Potential energy , i.e.
(1/2) mv^2 = mg[h(net)]
According to question, h = 100 - 30 + 10 = 80m & g = 10m/sec^2
On putting the values, we get v = 40 m/sec