Rolling forever

Suppose I have a line of squares, labelled 0 , 1 , 2 , 3 , 4 , 0,1,2,3,4, \ldots . I place a marker on the square 0. On every turn, I roll a die (with the numbers 1 to 6 and move forward as follows: if I was on square P P before the roll and I get a x x then I move to square P + x P+x . Let X n X_n be the chance that I land on the square labelled n n . What is

lim n X n ? \displaystyle \lim_{n \rightarrow \infty} X_n ?

1 2 \frac{1}{2} 1 6 \frac{1}{6} 1 3 \frac{1}{3} 2 7 \frac{2}{7}

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1 solution

Lukas Riegler
Jan 13, 2019

Intuitive solution: The average number of squares the marker moves with each roll is 7 2 \frac{7}{2} .

So (in the long run) the marker will visit around 2 7 \frac{2}{7} of the squares. As n n\to\infty the probability converges to 2 7 \frac{2}{7} .

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