Rolling is cool! - 2

A uniform solid cylinder of mass m = 2 kg m = 2\text{ kg} is given and angular velocity of ω = 5 rad/sec \omega = 5\text{ rad/sec} and is dropped from a height of h = 22 m h = 22 \text{ m} on a rough floor at t = 0 t = 0 .

It collides with the sufficiently rough ground such that its velocity in the vertical direction reduces to zero.

Find the time, t t (in seconds) after which it starts pure rolling.

Details and Assumptions :

  • Coefficient of friction of ground is μ = 0.2 \mu = 0.2 .

  • Radius of cylinder is R = 2 m R = 2 \text{ m} , g = 10 m/s 2 g = 10\text{ m/s}^2 .

  • Initial height measured is of centre of mass of cylinder from ground.


Try more here


The answer is 2.000.

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

Rajdeep Dhingra
Aug 11, 2016

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...