Romanov's Integral

Calculus Level 5

This integral comes from my personal research and IMHO, it should be a level 5 problem. Why? First, neither Wolfram|Alpha nor Mathematica can return a plausible closed-form for this integral. Not only a closed-form that they failed to give, but also its numerical value to the precision of only 10 digits (using normal procedure). Second, it has been posted at four different sites such as: Mathematics StackExchange , Integrals and Series , AoPS , and Quora , but none exact solution has been given yet . So, if you could answer it, would you care to post the solution? Here is the problem:


R = 0 π 2 sin 2 x ln ( sin 2 ( tan x ) ) d x = π α ln ( e β γ δ ) π μ ( e ν θ e λ ψ ) + ω \large\mathscr{R}=\int_0^{\Large\frac{\pi}{2}}\sin^2x\,\ln\big(\sin^2(\tan x)\big)\,\,dx=\frac{\pi}{\alpha}\ln\left(\frac{e^\beta-\gamma}{\delta}\right)-\frac{\pi}{\mu}\left(\frac{e^\nu-\theta}{e^\lambda-\psi}\right)+\omega

where α , β , γ , δ , μ , ν , θ , λ , ψ , ω \large \alpha,\beta,\gamma,\delta,\mu,\nu,\theta,\lambda,\psi,\omega are non-negative integers and square-free. Find α + β + γ + δ + μ + ν + θ + λ + ψ + ω \large \alpha+\beta+\gamma+\delta+\mu+\nu+\theta+\lambda+\psi+\omega ?


The answer is 15.

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1 solution

Julian Poon
Nov 23, 2014

There is already a solution here

Thanks for sharing that link. I think I know the one who posts this problem there. Haha

Anastasiya Romanova - 6 years, 6 months ago

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Which is you

Julian Poon - 6 years, 6 months ago

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