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Geometry Level 1

Find the equation of a plane passing through the point ( − 1 , 0 , − 1 ) (-1,0,-1) parallel to the x z xz -plane.

y = 0 y=0 − x − z = 0 -x-z=0 y = − 2 y=-2 None of the above

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Sandeep Bhardwaj by Sandeep Bhardwaj , 28, India

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2 solutions

Ali Rizvi
May 6, 2017

Equation of plane which is parallel to xz-plane is given by.... y=b ,b is distance on y-axis
Since the plane is passing through the point (-1,0,-1) therefore b=o Hence the required equation is y= o

9 Helpful 0 Interesting 0 Brilliant 3 Confused

y=0 is the equation of xz-plane. They are not parallel.

Vm Loc - 2 years, 4 months ago
Anand Jha
Feb 18, 2019

Here in xz plane the coordinates of y = b . So y=0

0 Helpful 3 Interesting 1 Brilliant 1 Confused

" a(x-x0)+b(y-y0)+c(z-z0) = 0 " -- This is the eq of plane ,,, Now here " x0 = -1 , y0 = 0 , z0 = -1 " given in question as a point on the plane ,,, Now " Let ( a,b,c ) = m ( vector ) which is perpendicular to xz plane ... That's why it's X axis and z axis components ( a,c ) = ( 0,0 ) and ,,, Now , the eq of plane will be " 0 (x+1)+ b (y-0) + 0 (z+1) = 0 " which is " b y = 0 " ,, that's why " y = 0 " is answer ,, Thank you .. If it helps you give a like ,,, Thank you.....

Indradeep Bhattacharyay - 1 year, 4 months ago

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