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Algebra Level 2

The value of 5 + 11 + 19 + 20 + 49 \sqrt{5+\sqrt{11+\sqrt{19+\sqrt{20+\sqrt{49}}}}} equals:

1 None of these choices 13 3

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1 solution

Atul Shivam
Oct 30, 2015

Just simply from last root up to first root you Will get finally 9 \sqrt{9} which is 3 \boxed{3}

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It is close to 3 3 but not exactly 3. 3. The 20 20 would need to be changed to 29 29 for this to be the case, in which case

5 + 11 + 19 + 29 + 49 = \sqrt{5 + \sqrt{11 + \sqrt{19 + \sqrt{29 + \sqrt{49}}}}} =

5 + 11 + 19 + 6 = 5 + 11 + 5 = 5 + 4 = 3. \sqrt{5 + \sqrt{11 + \sqrt{19 + 6}}} = \sqrt{5 + \sqrt{11 + 5}} = \sqrt{5 + 4} = 3.

Brian Charlesworth - 5 years, 7 months ago

I think problem is o v e r r a t e d o^{v^{e^{r^{r^{a^{t^{e{^d}}}}}}}} :p

Atul Shivam - 5 years, 7 months ago

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