3 1 2 5 lo g 5 4 + lo g 5 3 = ?
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I tried to solve this problem but I can't able to understand your 5th step ...will u please explain clearly... Macnath kotapatti ravichandran, EIE branch, LPU universtity, India.
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Hi @macnath mac ! What is done in the fifth step is described as a l o g a b = b , which is one of the properties of logarithms.
I couldn't understand the step in which you removed log( i only know basics of log) Can you please explain it.
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If you have log base "b", and you have b^(logb(a)). Then you can logic it out. Log functions take the bottom number and make the exponent required to make b turn into a. Using this logic, if log is the exponent to make b turn to a, then b to the log b of a is just "a". For future reference, if you have something like e^(in(a)), you can simplify to "a".
= 3 1 2 5 lo g 5 4 + lo g 5 3
= 3 1 2 5 lo g 5 1 2 ( log Property: lo g a b + lo g a c = lo g a b c )
= 3 5 3 lo g 5 1 2
= 3 5 lo g 5 1 2 3 ( log Property: p lo g a b = lo g a b p )
= 3 1 2 3 ( log Property: a lo g a b = b )
= 1 2
See: b LOG b x + LOG b y = x y
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3 1 2 5 lo g 5 4 + lo g 5 3 = A → 3 1 2 5 lo g 5 1 2 → 3 5 3 lo g 5 1 2 → 3 5 lo g 5 1 2 3 → 3 1 2 3 → 1 2 = A