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Thanks, I've updated the answer.
Hah! You must be kidding me! This is by far the most easiest sum I have encountered here on Brilliant. Just use the Vieta's formula to find the product of the roots for the quadratic polynomial.
If roots are α , β , then,
\Large \alpha + \beta = \frac{-\text{Coefficient of x}}{\text{Coefficient of x^2}}
and, \Large \alpha. \beta = \frac{\text{Constant term}}{\text{Coefficient of x^2}}
ok..thanks a lot
roots of equation are 4,1 so product is 4
after factorization the two roots are (2-i) & (2+i) therefor the product of them is 4-i^2 and since i^2=-1 therefore 4-i^2 = 5
thnaks for your good contribution
Thank you!
Vieta's Formulas: x1 + x2 = -b/a x1*x2=c/a
The answer is correct, it's -5
multiplication of root is c/a
C/A =products of zero Hence ans =5/1
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The answer must be 5. Product of roots=c/a=5