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x = 2 0 1 7 + 2 0 1 7 + 2 0 1 7 + . . . + 2 0 1 7 x 2 = 2 0 1 7 + x x 2 − x − 2 0 1 7 = 0
Based on 2 a − b ± b 2 − 4 a c
x 1 , x 2 = 2 ⋅ 1 − ( − 1 ) ± ( − 1 ) 2 − 4 ⋅ 1 ⋅ ( − 2 0 1 7 ) x 1 , x 2 = 2 1 ± 1 + 8 0 6 8 x 1 , x 2 = 2 1 ± 8 0 6 7 x 1 , x 2 ≈ 2 1 ± 8 9 . 8 2 x 1 ≈ 2 1 + 8 9 . 8 2 ⇒ 4 5 . 4 3 x 2 ≈ 2 1 − 8 9 . 8 2 ⇒ − 4 4 . 4 3
Since the result of the square root is always positive, so the value of x that satisfies is 4 5 . 4 3 . So, ⌊ x ⌋ = 4 5