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1 solution
l i m x → ∞ x ( x + 2 0 − x ) = l i m x → ∞ ( x + 2 0 + x ) x ( x + 2 0 − x ) ( x + 2 0 + x ) = l i m x → ∞ ( x + 2 0 + x ) 2 0 x = l i m x → ∞ ( 1 + x 2 0 + 1 ) 2 0 = 2 2 0 = 1 0