Root problem

Algebra Level 4

If p p , q q and r r are real roots of equation x 3 9 x 2 + 24 x + c = 0 x^3-9x^2+24x+c=0 , find the minimum value of p + q + r \lfloor p \rfloor + \lfloor q \rfloor +\lfloor r \rfloor .

Notation: \lfloor \cdot \rfloor denotes the floor function .


The answer is 7.

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1 solution

Prajwal Krishna
Nov 17, 2016

p+q+r = 9

[p]+{p}+[q]+{q}+[r]+{r} = 9

[p]+[q]+[r] = 9 - ( {p}+{q}+{r})

0 <= {x}< 1

So 0 <= {p}+{q}+{r} <3

Hence minimum integral value of [p]+[q]+[r] = 7

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