Roots

Algebra Level 3

Given that q 2 − 4 p r = 0 q^{2} - 4pr = 0 and q p = 1.6 \dfrac qp = 1.6 , find the the sum of roots of the equation below:

p x 3 + ( p + q ) x 2 + ( q + r ) x + r = 0 \large px^{3} + ( p+q)x^{2} + (q + r )x + r = 0


The answer is -2.6.

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1 solution

Vilakshan Gupta
Oct 3, 2017

sum of roots= − ( b a ) -\left(\frac{b}{a}\right) = − ( p + q ) p = − 1 − q p = − 1 − 1.6 = − 2.6 -\frac{(p+q)}{p}=-1-\frac{q}{p}=-1-1.6=\boxed{-2.6}

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