f ( x ) 2 + 3 f ( x ) + 2
If f ( x ) = x 2 − 8 x , then the equation above has 4 distinct real roots of the form 4 ± a for real value a .
Denote the sum of all values of a as S . Evaluate S 1 7 4 0 .
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f ( x ) 2 + 3 f ( x ) + 2 = ( f ( x ) + 1 ) ( f ( x ) + 2 )
⇒ f ( x ) 2 + 3 f ( x ) + 2 = ( x 2 − 8 x + 1 ) ( x 2 − 8 x + 2 ) = 0
x 2 − 8 x + 1 = 0 ⇒ x = 4 ± 1 5
x 2 − 8 x + 2 = 0 ⇒ x = 4 ± 1 4
Let the values of a be a 1 , a 2
S = a 1 + a 2 = 2 9 ⇒ S 1 7 4 0 = 2 9 1 7 4 0 = 6 0
f(x) = -1 or f(x)=-2 so solving it we get either 4+√15 or 4 - √15 and 4+√14 or 4-√14 So S = 15+14 =29. 1740/29 =60
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