Roots of a Quartic

Algebra Level 3

f ( x ) 2 + 3 f ( x ) + 2 \large f(x)^2+3f(x)+2

If f ( x ) = x 2 8 x f(x)= x^2-8x , then the equation above has 4 distinct real roots of the form 4 ± a 4 \pm{\sqrt{a}} for real value a a .

Denote the sum of all values of a a as S S . Evaluate 1740 S \dfrac {1740}S .


The answer is 60.

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3 solutions

Devin Ky
Jun 24, 2015

f ( x ) 2 + 3 f ( x ) + 2 = ( f ( x ) + 1 ) ( f ( x ) + 2 ) f(x)^2 + 3f(x) + 2 = (f(x) + 1)(f(x) + 2)

f ( x ) 2 + 3 f ( x ) + 2 = ( x 2 8 x + 1 ) ( x 2 8 x + 2 ) = 0 \Rightarrow f(x)^2 + 3f(x) + 2 = (x^2 - 8x + 1)(x^2 - 8x + 2) = 0

x 2 8 x + 1 = 0 x = 4 ± 15 x^2 - 8x + 1 = 0 \Rightarrow x = 4 \pm \sqrt{15}

x 2 8 x + 2 = 0 x = 4 ± 14 x^2 - 8x + 2 = 0 \Rightarrow x = 4 \pm \sqrt{14}

Let the values of a a be a 1 , a 2 a_1 , a_2

S = a 1 + a 2 = 29 1740 S = 1740 29 = 60 S = a_1 + a_2 = 29 \Rightarrow \dfrac{1740}{S} = \dfrac{1740}{29} = \boxed{60}

Mehul Bafna
Jun 20, 2015

f(x) = -1 or f(x)=-2 so solving it we get either 4+√15 or 4 - √15 and 4+√14 or 4-√14 So S = 15+14 =29. 1740/29 =60

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