Roots of Quadratic

Algebra Level 3

Consider real numbers m m and n n such that 1 + 2 i -1+2i is a root of the quadratic equation x 2 + m x + n = 0 x^2+mx+n=0 . If m m and n n are the two roots of the quadratic equation x 2 + A x + B = 0 x^2+Ax+B=0 , what is the value of B A B-A ?

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1 solution

Tom Engelsman
Nov 9, 2020

The two roots in question are complex conjugate pairs 1 ± 2 i -1 \pm 2i , which after applying Vieta's Formulae gives:

m = [ ( 1 + 2 i ) + ( 1 2 i ) ] = 2 m=-[(-1+2i)+(-1-2i)] = 2 ;

n = ( 1 + 2 i ) ( 1 2 i ) = 5 n = (-1+2i)(-1-2i) = 5 .

Now if m m and n n are the roots to x 2 + A x + B = ( x m ) ( x n ) = ( x 2 ) ( x 5 ) = 0 x^2 + Ax +B = (x-m)(x-n) = (x-2)(x-5) = 0 , then A = 7 , B = 10 B A = 17 . A = -7, B = 10 \Rightarrow B-A = \boxed{17}.

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