Roots of unity for beginners 2

Algebra Level 4

How many roots have an integral real part for

x 3 + x 2 + x + 1 = 0 ? x^3+x^2+x+1=0?

2 0 4 1 3

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1 solution

Dev Sharma
Dec 8, 2015

Let p ( x ) = x 3 + x 2 + x + 1 = 0 p(x) = x^3 + x^2 + x + 1 = 0

By Rational Root Theorm , we found that x = 1 x = - 1 is a root of p ( x ) p(x) , so we can factor it out :

( x + 1 ) ( x 2 + 1 ) = 0 (x + 1)(x^2 + 1) = 0

so roots are 1 , i , i -1, i, -i and there real parts are 1 , 0 , 0 -1, 0, 0 respectively. So answer is 3.

Nice solution..

A Former Brilliant Member - 5 years, 6 months ago

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Thank You....

Dev Sharma - 5 years, 6 months ago

I thought only -1 have real part, and answer is 1.

Zakir Dakua - 5 years, 6 months ago

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Same mistake ! Ought to give some respect to 0 .

Raven Herd - 5 years, 3 months ago

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