Roots progression?

Algebra Level 4

If a , b , c \color{#D61F06}a , \color{#3D99F6}b , \color{#69047E}c are in Arithmetic Progression. Then 1 b + c , 1 c + a , 1 a + b \dfrac{1}{\sqrt{\color{#3D99F6}b} + \sqrt{\color{#69047E}c}} , \dfrac{1}{\sqrt{\color{#69047E}c} + \sqrt{\color{#D61F06}a}} , \dfrac{1}{\sqrt{\color{#D61F06}a} + \sqrt{\color{#3D99F6}b}} are in ..................

Clarification : a , b , c > 0 \color{#D61F06}a , \color{#3D99F6}b , \color{#69047E}c > 0

None of these Arithmetic - geometric progression Geometric progression Arithmetic progression Harmonic progression

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

Pulkit Gupta
Nov 27, 2015

a , b & c are in an A.P. Thus, b - a = c - b implying { b \sqrt{b} - a \sqrt{a} } { b \sqrt{b} + a \sqrt{a} } = { c \sqrt{c} - b \sqrt{b} } { c \sqrt{c} + b \sqrt{b} }

We claim that the given terms are in A.P. Then, the difference of two consecutive terms should be same. On using the above equation coupled with this fact; we can easily prove that our claim is indeed true.

@Pulkit Gupta Take a = x y , b = x , c = x + y a = x - y , b = x , c = x + y

Then rationalize the given terms and you'll directly see that they are in AP.

Ankit Kumar Jain - 4 years, 2 months ago

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...