For a constant , the two roots of the quadratic equation are and What is the value of
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Relevant wiki: Vieta's Formula Problem Solving - Intermediate
If sin θ and cos θ are roots of 3 x 2 − x + k = 0 , then by Vieta's formula:
⎩ ⎪ ⎨ ⎪ ⎧ sin θ + cos θ = 3 1 sin θ cos θ = 3 k . . . ( 1 ) . . . ( 2 )
And we have:
( sin θ + cos θ ) 2 9 1 ⟹ k = sin 2 θ + 2 sin θ cos θ + cos 2 θ = 1 + 3 2 k = − 3 4
Also:
sin 3 θ + cos 3 θ = ( sin θ + cos θ ) ( sin 2 θ + cos 2 θ − sin θ cos θ ) = 3 1 ( 1 + 9 4 ) = 2 7 1 3
⟹ 5 4 ( sin 3 θ + cos 3 θ ) = 2 6 .