Rotating turntable with a ball

The turntable shown in figure is rotated with constant ω = 2 \omega = 2 rad/sec. A ball of mass 3 kg is gently placed in a frictionless tunnel at a distance 3 3 3\sqrt3 m from the center. Find the radial velocity of ball (in m/s) when it reaches at the end of the tunnel provided, the length of the tunnel is 14 m.


The answer is 26.

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

We know that

F = d p / d t = m d v / d t = m d v / d t d x / d x = m d x / d t d v / d x = m v d v / d x F=dp/dt=mdv/dt= m dv/dt dx/dx= m dx/dt dv/dx= mv dv/dx

And the radial force normal is

F = m V 2 / x = m w 2 x F=m V^2/x=mw^2 x

Equaling these equations we get

v d v / d x = w 2 x vdv/dx=w^2 x so v d v = w 2 x d x vdv= w^2 xdx

Integrating in both sides

v 2 = w 2 ( R 2 R 0 2 ) v^2=w^2 (R^2 - R0^2) V = w R 2 R 0 2 = 26 V= w \sqrt{R^2-R0^2}=26 m/s

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...