Rotation is fun
A ROD OF MASS M AND LENGTH L IS HIT PERPENDICULARLY AT ONE OF ITS END.THE VELOCITY OF THE END OF THE ROD JUST AFTER THE HIT IS V.IF W IS THE NET WORK DONE BY THE EXTERNAL FORCE ON THE ROD,A= .IF THE DISTANCE OF THEINSTANTANEOUS AXIS OF ROTATION FROM THE POINT WHERE IT WAS INITIALLY HIT IS X.B= . FIND A + B.
The answer is 10.
This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try
refreshing the page, (b) enabling javascript if it is disabled on your browser and,
finally, (c)
loading the
non-javascript version of this page
. We're sorry about the hassle.
1 solution
CONSIDER VELOCITY OF OF COM AS V(0),VELOCITY OF THE END(SAY A) WRT COM AS V(1). LET IMPULSE J=MV(0) USE IMPULSE ANGULAR MOMENTUM THEOREM ABOUT COM....U WILL GET V(0)= 3 V ( 1 ) NOW V-V(O)=V(1).....U WILL EASILY GET ON SOLVING V(0)= 4 V . THEN WORK DONE = CHANGE IN KE....U WILL GET W= 8 M ∗ V 2 THE AXIS OF ROTATION IS WHERE ...V-(omega)*X=0.....U WILL GET X= 3 2 ∗ L HENCE A=8,B=2,A+B=10(ANS).