Rouge Rope

Calculus Level 3

A rectangle A of 7 cm. width and 21 length is surrounded by a rope of the perimeter's length. Then the same rope is relocated to border rectangle B and square C such that rectangles A & B are similar as shown.

What is the smallest total areas of rectangle B and square C in c m 2 cm^{2} ?


The answer is 84.

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1 solution

The rope's length = rectangle's perimeter = 2(7+21) = 56.

If we let x = rectangle B's width, B's length = 3x. Hence, square C's side = (56 - 8x)/4 = 14 - 2x.

f(x) = total areas of B+C = 3 x 2 x^{2} + ( 14 2 x ) 2 (14 - 2x)^{2} = 7 x 2 x^{2} - 56x + 196

f '(x) = 14x - 56 = 0; x = 4. So the minimum is at f(4) = 84.

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