Find sum of all real solution of which satisfies
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if ∣ x ∣ = k then x = k or x = − k
then ∣ ∣ ∣ ∣ x + 2 ∣ + 0 ∣ + 1 ∣ + 5 = 2 0 1 5 or − 2 0 1 5
implies that ∣ ∣ ∣ ∣ x + 2 ∣ + 0 ∣ + 1 ∣ = 2 0 1 0 or − 2 0 2 0
but since ∣ x ∣ never be negative, so apply this until you get ∣ x + 2 ∣ = 2 0 0 9
then x + 2 = 2 0 0 9 or x + 2 = − 2 0 0 9
we got that x = 2 0 0 7 or x = − 2 0 1 1 add those and the answer is − 4