RPS #005 - Dimensional Geometry

Geometry Level 3

Consider a right triangle named A B C ABC with A B AB as its hypotenuse. D D is a point on B C BC such that A D AD is the angle bisector of B A C \angle BAC . E E is a point on A B AB such that A D E = 9 0 \angle ADE = 90 ^ \circ .

The value of B C × A E A B × C D \frac{BC \times AE}{AB \times CD} is?


The answer is 2.

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1 solution

Rimba Erlangga
Jan 23, 2015

Im sorry for the mistake of the problem. Here is the solution n

You can use trig identity s i n 2 α = 2 × s i n α × c o s α sin 2\alpha = 2 \times sin \alpha \times cos\alpha on both small and big right triangle

Cn u plz prvide a diagram fr the prblm ..... Hw cme AD be the bisectr of angle ABC ??it shld be BD eithr...?

tanmay goyal - 6 years, 4 months ago

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The same question is in my mind

karandeep singh ludhar - 6 years, 4 months ago

Thanks. I've rewritten the question to help with clarity. Can you review it for accuracy?

Calvin Lin Staff - 6 years, 4 months ago

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ok thx sir

Rimba Erlangga - 6 years, 4 months ago

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