RRemainderrr part 2

Find the remainder when ( 1!+2!+3!............................+100!) is divided by 5.


The answer is 3.

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2 solutions

The values 5!,6!,7!..........100! all have 5 as a factor so, remainder must be 1!+2!+3!+4! / 5 which is 33/5 which is 3 .

i have already posted this question !!!!

Rishabh Jain - 7 years ago

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you can check it here

Rishabh Jain - 7 years ago
William Isoroku
Aug 1, 2014

every number after 4! has a 0 in its units digit. So just add 1!+2!+3!+4! which is 33, which leaves 3 as a remainder when divided by 5.

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