Suppose that, in a perfectly competitive market, the quantity Q that is demanded of a certain product as a function of the price P is Q = a − b P , for some constants a and b . What is the absolute value of the elasticity of demand at the quantity that maximizes revenue?
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The elasticity of demand is given by
∣ ∣ ∣ ∣ d P d Q × Q P ∣ ∣ ∣ ∣ .
The total revenue a company can make is equal to P Q . Since P = b a − Q , we have
P Q = b Q ( a − Q ) = b a Q − Q 2 .
The quantity that maximizes revenue can be found by taking the derivative of the above expression:
d Q d b a Q − Q 2 = b a − 2 Q .
Setting this equal to 0, we find Q = 2 a . Since the second derivative is always negative, the revenue is maximized at this value.
We have d P d Q = − b from our function. Thus, the elasticity equals
∣ ∣ ∣ ∣ − Q b P ∣ ∣ ∣ ∣ = ∣ ∣ ∣ ∣ ∣ ∣ − Q b ( b a − Q ) ∣ ∣ ∣ ∣ ∣ ∣ = ∣ ∣ ∣ ∣ − Q a − Q ∣ ∣ ∣ ∣ .
Plugging in Q = 2 a , we find that the elasticity equals 1 .
I feel like negative signs are appropriate or at least acceptable -1 should be counted as correct; or it could be mentioned to take abs.
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Clearly, a perfectly elastic demand curve would maximise the quantity