A quantitative finance problem by Steven Yuan

Suppose that, in a perfectly competitive market, the quantity Q Q that is demanded of a certain product as a function of the price P P is Q = a b P Q = a - bP , for some constants a a and b b . What is the absolute value of the elasticity of demand at the quantity that maximizes revenue?


The answer is 1.

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

2 solutions

Clearly, a perfectly elastic demand curve would maximise the quantity

Steven Yuan
Jun 2, 2015

The elasticity of demand is given by

d Q d P × P Q . \left | \frac{dQ}{dP} \times \frac{P}{Q} \right |.

The total revenue a company can make is equal to P Q PQ . Since P = a Q b P = \frac{a - Q}{b} , we have

P Q = Q ( a Q ) b = a Q Q 2 b . PQ = \frac{Q(a - Q)}{b} = \frac{aQ - Q^2}{b}.

The quantity that maximizes revenue can be found by taking the derivative of the above expression:

d d Q a Q Q 2 b = a 2 Q b . \frac{d}{dQ} \; \frac{aQ - Q^2}{b} = \frac{a - 2Q}{b}.

Setting this equal to 0, we find Q = a 2 Q = \frac{a}{2} . Since the second derivative is always negative, the revenue is maximized at this value.

We have d Q d P = b \frac{dQ}{dP} = -b from our function. Thus, the elasticity equals

b P Q = b ( a Q b ) Q = a Q Q . \left | - \frac{bP}{Q} \right | = \left | - \frac{b \left (\frac{a - Q}{b} \right)}{Q} \right | = \left | - \frac{a - Q}{Q} \right |.

Plugging in Q = a 2 Q = \frac{a}{2} , we find that the elasticity equals 1 \boxed{1} .

I feel like negative signs are appropriate or at least acceptable -1 should be counted as correct; or it could be mentioned to take abs.

Xian Ng - 6 years ago

Log in to reply

Those who answered -1 have been marked correct.

In future, if you spot any errors with a problem, you can “report” it by selecting "report problem" in the menu. This will notify the problem creator who can fix the issues.

Calvin Lin Staff - 5 years ago

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...