Salt Analysis!
You take a salt and add dilute , you see that a gas evolves which turns lime water milky. Which of the following may be the salt?
A. Magnesium Carbonate .
B. Magnesium Sulphite.
C. Magnesium Sulphide.
D. Barium Sulphate .
E. Calcium Carbonate.
F. Calcium Sulphide.
G. Barium Nitrate.
This is a part of my set Inorganic Fun
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1 solution
This is a very detailed solution
We have two groups of Anions viz A And B .
Group A Anions are those which can be identified by the volatile substances they produce on reaction with acid .
Group B Anions are those which are identified by there reactions in solutions.
Further Groups A And B Are divided into two parts
Group A Is subdivided into anions which react with dilute acids and those which react with concentrated acids.
Dilute acids- Sulphite , Sulphide , Carbonate , Bicarbonate, Acetate ,Nitrite and thiosulphate
Concentrated Acids- Chlorides, Bromides , Iodides , Oxalate , Nitrate
Group B Is subdivided into anions which are identified by precipitation and redox
Precipitation- Phosphates and sulphates
Redox- Manganate , Permanganate , Chromate , Dichromate
In the given problem the compound is reacting with dilute HCl means it must be Group A.
Now sulphides on treatment with H+ Gives H2S Which does not produce turbidity with lime water.
So it can be a carbonate or sulphite which produce CO2 And SO2 Respectively on treatment with Acid
Therefore the correct answer Is A,B,E.