If the area of equilateral triangle XYZ is equal to area of rhombus ABCD, in which Angle A = 60°,
Then which will have greater perimeter?
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Let the rhombus have side length a . It’s perimeter is 4 a . Since one angle is 6 0 ∘ , divide the rhombus into 2 equilateral triangles. Each has area 2 1 a 2 sin 6 0 = 4 3 a 2 . Therefore the area of the rhombus & △ X Y Z is 4 3 ( 2 a 2 ) . That makes each triangle side 2 a 2 = 2 a . The perimeter is 3 2 a . 3 2 > 4 so the triangle has the greater perimeter.