Same Base, But Different Exponents

Algebra Level 3

Let f ( x ) = ( 1 x 3 ) 2 + 5 f(x)=\left ( 1-x^3 \right )^{2+\sqrt{5}} , g ( x ) = ( 1 x 3 ) 2 5 \;g(x)=\left ( 1-x^3 \right )^{2-\sqrt{5}} and h ( x ) = ( 1 x 3 ) ( 2 + 5 ) h(x)=\left ( 1-x^3 \right )^{-(2+\sqrt{5})} .

Which of these affirmations about their real domains is true ?

The domains of f ( x ) f(x) and g ( x ) g(x) are the same The domains of f ( x ) f(x) and h ( x ) h(x) are the same The domains of f ( x ) f(x) , g ( x ) g(x) and h ( x ) h(x) are all the same The domains of g ( x ) g(x) and h ( x ) h(x) are the same The domains of f ( x ) f(x) , g ( x ) g(x) and h ( x ) h(x) are different from each other

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1 solution

Jaydee Lucero
Jun 27, 2017

Note that 2 + 5 2+\sqrt{5} is positive, while 2 5 2-\sqrt{5} and ( 2 + 5 ) -(2+\sqrt{5}) are both negative. So write

f ( x ) = ( 1 x 3 ) 2 + 5 , g ( x ) = 1 ( 1 x 3 ) 2 + 5 , h ( x ) = 1 ( 1 x 3 ) 2 + 5 f(x)=(1-x^3)^{2+\sqrt{5}},g(x)=\frac{1}{(1-x^3)^{-2+\sqrt{5}}},h(x)=\frac{1}{(1-x^3)^{2+\sqrt{5}}}

Note that 1 x 3 = ( 1 x ) ( 1 + x + x 2 ) 1-x^3 = (1-x)(1+x+x^2) . Therefore, the domain of f f is all real numbers, while the domain of g g and h h are both all real numbers except x = 1 x=1 . Thus, the domains of g g and h h are the same .

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