Same five digits

The conditions: "Each of the five digits is used a different number of times, the five numbers of times being the same as the five digits of the perfect squares" indicates that the possible digit integers can only be 1, 2, 3, 4 and 5. Because the sum of the numbers of times the five digits are used is 15 = 3 $\times$ 5 digits = 1 + 2 + 3 + 4 + 5. A program as the one below (Python) can be written to find the valid 5-digit perfect squares. And they are 12321, 12544, 13225, 33124, 34225, 35344, 44521, and 52441. By try-and-error (I am no good in writing program), it is found that The three 5-digit perfect squares that meet the condition: "No digit is used its own number of times" are 12321, 33124 and 34225, where digits appear 1, 2, 3, 4, and 5 times are 5, 4, 1, 3 and 2 respectively. The answer is therefore $12321+33124+34225=\boxed{79670}$ .

squares = []
 OK = "N"
 for i in range(100,236):
     s = i*i
     ss = str(s)
     if OK=="Y":
    squares.append((i-1)*(i-1))
OK="Y"
for j in range(len(ss)):
    for k in [0, 6, 7, 8, 9]:
        if int(ss[j])==k:
            OK = "N"
            break
    if OK=="N":
        break